Experiment 22 Report Sheet Molar Solubility, Common-lon Effect te Lab Sec.Name D

Question

Experiment 22 Report Sheet Molar Solubility, Common-lon Effect te Lab Sec.Name Desk No. . Molar Solubility and Solubility Product of Calcium Hydroxide Trial I Trial 2 Trial3 1. Volume of saturated CalOH), solution (ml.) 25.0 25.0 25.0 2 Concentration of standardized HCl solution (moV/L) 3. Buret reading, initial (mL) Ml 4Buret reading.final (ml) 5. Volume of HCI added (L) 6. Moles of HCl added (mot 7. Moles of OH in saturated solution (mol) 8. IOH1, equilibrium (moVL 9. ICa, equilibrium (moL 10. Molar solubility of Ca(OH) (moVL) 11. Average molar solubility of CalOH) Omo 12. K of CaOH) Average K 14. Standard deviation of K, 15. Relative standard deviation of K-%RSD) Date Analysis, IB Data Analysis, Data Analysis, D Calculations for Trial

Explanation / Answer

Q6.

moles of HCl added --> MV = 0.05 mol/L * 17.9 mL * 10^-3 L/mL = 0.000895 mol

Q7.

moles of OH- in solution

OH- = H+

then

mol of OH- = 0.000895 mol

Q8

[OH-] = mol of OH- / V of solution = 0.000895 / (25*10^-3) = 0.0358 M

Q9

by stoichiometry

Ca(OH)2 = Ca+2 + 2OH-

then

if OH = 0.0358

then

[Ca+2+] = 1/2*[OH-]= 1/2*0.0358 = 0.0179 M

Q10

Molar solubility

1 mol of Ca(OH)2 = 1 mol of Ca

0.0179 M of Ca+2 = 0.0179 M of Ca(OH)2

Solubility of Ca(OH)2 = 0.0179 M

Q12.

KSp = [Ca2+][OH-]^2

KSp = (0.0179)* ( 0.0358 ^2)

Ksp = 0.0000229

Ksp = 2.29*10^-5

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