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B-False A-True Questions (S-7) True or False 5. is still warm compared to room t

ID: 555136 • Letter: B

Question

B-False A-True Questions (S-7) True or False 5. is still warm compared to room temperature, there are convection currents When a crucible due to the emperature differential, resulting in increased mass of the crucible. (4 points) ties, students should 6. Alum crystals usually contain several impurities. To remove these impuri wash the crystals with pure water to remove them. (4 points) 7. In a solution, strong acids and bases are known to partially ionize, but weak acids and bases always ionize completely. (4 points) Questions (8-11) Match the following as soluble salt (SS), insoluble salt (IS), strong weak acid (WA), strong base (SB), weak base (WB), insoluble hydroxide (TH), or (3 pts each, 12 points) acid (SA), molecule (M). 8. Ca(OH)a 9. BaSO4 10. HNO 11.HF a. Soluble salt b. Insoluble salt c. Strong acid d. Strong base e. Insoluble hydroxide ab. Weak acid ac. Weak base ad. Molecule 12. In the following reaction: 2KCI + BaF2 2 KF + BaCl2 60 grams of KCl is reacted with 40 grams of BaF2 What is the limiting reagent? (5 points) a. KF b. BaF2 c. BaCh d. KCI /29 Poge 2 of 4 Version B

Explanation / Answer

Q5.

FALSE, evne though all is statec correctly, the convectiv eforce will "pull" the cruicible, therefore, "decreased mass" will appear

Q6

False.

We tpyically try to recrlystallize it as well

Q7

False, storng acids/bases ionize at 100% and weak acids/bases will ionzie aprtially, the statement is inverted

Q8

Ca(OH)2 is slightly soluble, 1.9 g per 100 g approx, therefore, choose insoluble hydroxide, since it is not that soluble

Q9

BaSO4 is not soluble, it is a salt, so choose insoluble salt

Q10

HNO3 is a strong acid, NO3- forms readily in solution, so this is strong acid

Q11

HF will ionize partially, so this is weak acid

Q12

mol of KCl = mass/MW = 60/74.5513 = 0.80481

mol of BaF2 = mass/MW = 40/175.3238064 = 0.228149

ratio is 2:1 so

0.228149 mol of BaF2 requires 0.228149*2 = 0.456298 mol of KCl, which we do hav,e so KCl i sin excess

limiting reagent must be BaF2