s/mod/ibis/view.php?id 4211681 sota, Twin Cities - CHEM 2101- Fall17- BANTZ Acti
ID: 555879 • Letter: S
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s/mod/ibis/view.php?id 4211681 sota, Twin Cities - CHEM 2101- Fall17- BANTZ Activities and Due Dates Ch1la o 11/8/2017 05:00 PM0/100 Grad Prt Calalator -d) Periodic Table Question 1 of 11 Sapling Learning A 25.00 mL sample of 0.300 M LiOH analyte was titrated with 0.750 M HI at 25 Calculate the initial pH before any titrant was added. pH= Calculate the pH of the solution after 5.00 mL of the titrant was added Number pH= Next Exit e Previous Give Up & View Solution 9 Check Answer abaut us careers privacy policy terms of use contact us F3 F6 F5 F4 8 4 5 6 3Explanation / Answer
a)
initial pH
[LiOH] = [OH-] = 0.3 M
pO H= -log([OH-]) = -log(0.3) = 0.522
pH = 14 - pOH =14-0.522
pH = 13.478
b)
mmol of titrant = MV = 0.75*5 = 3.75
mmol of base = MV = 0.3*25 = 7.5
mmol of base left = 7.5-3.75 = 3.75
Vtotal = 25+5 = 30
[OH-] = mmol/V = 3.75/30
[OH-] = 0.125
pH = 14 + logOH) = 14+ log(0.125)
pH = 13.096
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