s/mod/ibis/view.phpid-2486552 y College CHEM 1310- Spring16 MIGYANKO Activities
ID: 972209 • Letter: S
Question
s/mod/ibis/view.phpid-2486552 y College CHEM 1310- Spring16 MIGYANKO Activities and Due Dates HW 21 4/21/2016 12:00 AM -Print 41.7/100 Calculator Periodic Table Donald McQuarrie Peter A. Rock-Ethan Galogly For the oxidation-reduction reaction equation given here, escate how many electrons are ranstered in the formation of one e how many electrons are transferred in the formation of one formula unit of prodtuct Number Explanation c table, we know that bromine forms-1 ions. Based on its position in the One formula unit of the product contains 3 of these ions. Thus, 3 Br atoms each gain 1 electron. Similarly, we can infer that scandium has a+3 charge in the product. One formula unit of the product contains 1 of these ions. Thus, 1 Sc atoms loses 1 electron.Explanation / Answer
In this reaction, scandium and bromine are in its elemental state, so their charges are zero. When the reaction happens, one of the reactant oxidize (loses electrons), and the other one is reduced (gains electrons). The oxidation numer for scandium is 3+, and the oxidation number for bromine is 1-, but it has to be multiplied by the number of molecules in the compound, which is 3 (-1*3= -3).
2Sc + 3Br2 ------------ 2Sc Br3
0 0 +3 -1*3
The compound needs a stable state, so the sum of all its charges has to be zero. (+3 - 3 = 0)
2 moles of scandium needs to release 3 electrons
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