Use the References to access important values if needed for this question. Consi
ID: 556173 • Letter: U
Question
Use the References to access important values if needed for this question. Consider the following system at equilibrium where .198 ki, and Kc = 34.5 , at 1.15x 103 K: 2SO2 (g) + 02 (g)=_ 2 SO3 (g) If the TEMPERATURE on the equilibrium system is suddenly increased The value of K.[-] A. Increases B. Decreases C. Remains the same The value ofa(_JAls greater than Kc B. Is equal to K C. Is less than K The reaction must: A Run in the forward direction to restablish equilibrium. B. Run in the reverse direction to restablish equilibrium C. Remain the same. Already at equilibrium. A. Increase. B. Decrease. C. Remain the same. The concentration of O2 will: Subriit Answer Retry Entire Group 9 more group attempts r Prevw re TeExplanation / Answer
First, let us define the equilibrium constant for any species:
The equilibrium constant will relate product and reactants distribution. It is similar to a ratio
The equilibrium is given by
rReactants -> pProducts
Keq = [products]^p / [reactants]^r
For a specific case:
aA + bB = cC + dD
Keq = [C]^c * [D]^d / ([A]^a * [B]^b)
a)
reaction is exothermic, therefore, it releases heat
if T increases, K must decreases, since heat will not favour products
b)
Qc will then favour reactants, i.e. decreases
Qc < K, in order to fvour products
c)
rund backwards/reverse, to favour the counterbalance
d)
O2 must increases, since SO3 is reacting in reverse
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.