8. How will a system originally at equilibrium respond to increase in pressure?

Question

8. How will a system originally at equilibrium respond to increase in pressure? a. b. c. d. The system will shift towards reactants The system will shift towards products The system will remain unchanged It depends on other factors 9. An acid-base pair: a b. c. is a weak acid and its conjugate base Is a strong acid and its conjugate base Is any acid and its conjugate base 10. Comparing weak acids and strong acids of equal concentrations which of the following statements is true a. b. c. The pH of the weak acid will be higher than the pH of the strong acid The pH of the strong acid will be higher than the pH of the weak acid The pH of both acids will be equal 11. The conjugate base of H,co, is: a. H,co, b. HcO, C. 12. The chemical equation 2H,()+ O, (e)+ 2H,O (B) is an example of a: a. Homogeneous equilibrium b. Heterogeneous equilibrium c. Homogeneous nonequilibrium d. Heterogeneous nonequilbrium 13. The chemical equation C (s) + HiE-CO (g) +H2 (g) is an example of a: a. Homogeneous equilibrium b. Heterogeneous equilibrium c. Homogeneous nonequilibrium d. Heterogeneous nonequilibriunm 14. If the K, of a reaction is 0.25 what would K, be of the reaction written in the reverse? a. 0.25 b. 1.0 c. 4.0 15. If a reaction has two steps and K1-0.50 and K2-025, what is Keq of the overall reaction? a. 0.75 b. 0.50

Explanation / Answer

8. The pressure increases the pressure decreases side or volume decreases side
shift the equilibrium.
d. it depends on other factor.>>>>answer
9. c. is any acid and it's conjugate base
10.strong acid PH value is less than the weak acid
a. The pH of weak acid will be higher than the PH of the strong acid.
11.H2CO3 --------> HCO3^-
   acid             conjugate base
b.HCO3^-
12. at equilibrium reactant and products are same phage is called homogenneous equilibrium.
a. Homogeneous equilibrium
14.Keq = 0.25
   reverse reaction = 1/keq
                    = 1/0.25 = 4
c. 4
15.keq = kf/kb
        = 0.5/0.25   = 2

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