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A student observes the following single displacement reactions. Each reaction pr

ID: 556636 • Letter: A

Question

A student observes the following single displacement reactions. Each reaction proceeds spontaneously.

3 Pb(NO3)2(aq) + 2 In(s) 2 In(NO3)3(aq) + 3 Pb(s)

3 Pb(NO3)2(aq) + 2 Cr(s) 2 Cr(NO3)3(aq) + 3 Pb(s)

3 Ni(NO3)2(aq) + 3 In(s) 2 In(NO3)3(aq) + 2 Ni(s)

In(NO3)3(aq) + Cr(s) Cr(NO3)3(aq) + In(s)

Pb(NO3)2(aq) +Ni(s) Ni(NO3)2(aq) +Pb(s)

Rank the metals from strongest to weakest reducing agent, with 1 being strongest.

Cr

      [ Choose ]            4            1            3            2            cannot determine      

Ni

      [ Choose ]            4            1            3            2            cannot determine      

In

      [ Choose ]            4            1            3            2            cannot determine      

Pb

      [ Choose ]            4            1            3            2            cannot determine      

Explanation / Answer

Cr :1

Ni : 3

In : 2

Pb : 4

Since all the other metals can reduce Pb , so Pb is the weakest reducing agent of all.

Cr can reduce In , and In can reduce Ni , so Cr becomes the strongest reducing agent.

So the order of reducing strength becomes :

Cr > In > Ni > Pb