A student observes the following single displacement reactions. Each reaction pr
ID: 556636 • Letter: A
Question
A student observes the following single displacement reactions. Each reaction proceeds spontaneously.
3 Pb(NO3)2(aq) + 2 In(s) 2 In(NO3)3(aq) + 3 Pb(s)
3 Pb(NO3)2(aq) + 2 Cr(s) 2 Cr(NO3)3(aq) + 3 Pb(s)
3 Ni(NO3)2(aq) + 3 In(s) 2 In(NO3)3(aq) + 2 Ni(s)
In(NO3)3(aq) + Cr(s) Cr(NO3)3(aq) + In(s)
Pb(NO3)2(aq) +Ni(s) Ni(NO3)2(aq) +Pb(s)
Rank the metals from strongest to weakest reducing agent, with 1 being strongest.
Cr
[ Choose ] 4 1 3 2 cannot determine
Ni
[ Choose ] 4 1 3 2 cannot determine
In
[ Choose ] 4 1 3 2 cannot determine
Pb
[ Choose ] 4 1 3 2 cannot determine
Explanation / Answer
Cr :1
Ni : 3
In : 2
Pb : 4
Since all the other metals can reduce Pb , so Pb is the weakest reducing agent of all.
Cr can reduce In , and In can reduce Ni , so Cr becomes the strongest reducing agent.
So the order of reducing strength becomes :
Cr > In > Ni > Pb
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