A student measures the potential of a cell made up with 1 MCuSO4 in one solution

Question

A student measures the potential of a cell made up with 1 MCuSO4 in one solution and 1 MAgNO3 in the other. There is a Cu electrodein the CuSO4 and an Ag electrode in theAgNO3, and the cell is set up as Ecell=EZn.Zn2+oxidationreaction+EPB2+.Pbreduction reaction.She finds that the potential, or voltage, of the cell, Ecell^0, is 0.45 V, and that the Cu electrode isnegative.
a.) At which electrode is oxidation occurring?
b.) Write the equation for the oxidation reaction.
c.) Write the equation for the reduction reaction.

Explanation / Answer

If the Cu electrode is negative, that means the electrons areflowing to it. Electrons flow from Anode to Cathode. The oxidation of Zinc is: 2Zn(s) --> 2Zn2+(aq) + 2e- The reduction of Lead is: Pb2+(aq) + 2e- --> Pb(s)

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