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15 REPORT FOR EXPERIMENT 16 ONS AND PROBLEMS to make sure that all the KHCO, was

ID: 556849 • Letter: 1

Question



15 REPORT FOR EXPERIMENT 16 ONS AND PROBLEMS to make sure that all the KHCO, was e KHCOs was reactod? QUESTIONs 1. What was done in the experiment to starting mass of KHCO,? less than the 2. Why is the mass of KCI Calulate the mals and srame of HOI present in the 6.0 ml or 6.0 M ICI 3. Calculate the moles used. mol HCl ,? Show su pport- react with 3.80 g KHCO 4. Would the 60 mL of 6.0 M HCI be sufficient to ing caleulations and explanation. &. Theoreticalls why should the moles of KHCO, and the moles of KCI produced same? 6. 1r3.000 g of K,CO, were used in this experiment (instead of KHCO3), a) What is the balanced equation for the reaction? (b) How many mililiters of 6.0 M HCl would be needed mL HCI e How many grams of KCl would be formed in the reaction? g KCl 102 - 136 -

Explanation / Answer

Q1

in order to favour total addition:

- add enoug acid to form CO2(g) and H2O, all base should react

Q2

mass of KCl accoriding to mass of KHCO3 per unit mol is much less, note that CO2(g) and H"O(l) formed as well

Q3

mol of HCl in:

mol = M*V = 6*6*10 ^-3 = 0.036 mol of HCl

Q4

mol of KHCO3 = mass/MW = 3.8/100.115 = 0.03795

ratio is 1 mol of KHCO3 : 1 mol of HCl

0.03795 mol of HCl required

0.03795 - 0.036 = 0.00195 mol of HCl extra required

this is NOT enough

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