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Which of the following is/are true concerning equilibrium constants? 1. When an

ID: 557248 • Letter: W

Question

Which of the following is/are true concerning equilibrium constants? 1. When an equilibrium constant is very large, the equilibrium mixture contains more reactants than products. 2. When an equilibrium constant is very small, the equilibrium mixture contains more products than reactants. 3. When an equilibrium constant is neither large nor small, the equilibrium mixture contains approximately equal amounts of reactants and products a. 1only b. 2 only C. 3 only d. 1and 3 CS2(g) + 3C12(g)? CCI4(g) + S2C12(g) At a given temperature, the reaction above is at equilibrium when (CS,] 7. M. ICCLJ-0.15 M, and [S,C]-0.35 M. What will be the direction of the reaction when the 0.050 M, [CL]-0.25 reactants and products have the following concentrations: (CS,)-0.14 M, ICI] o.20 M, [CCla) 0.28 M, and [S CI1 0.28 M? a. to the left b. to the right c. no change d. cannot predict unless we know the temperature e. cannot predict unless we know whether the reaction is endother e or exothermic 8. Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb) sites according to the following equilibrium: Hb(02)4(aq) + 4C0(g) Hb(CO),(aq) + 402(g) From Le Châtelier's principle, CO poisoning is reversed by a. increasing the 02 pressure. b. decreasing the amount of Hb. C increasing the CO2 pressure. d. increasing the CO pressure. e increasing the amount of Hb.

Explanation / Answer

6) answer c

    equilibrium constant K=[Products]/[Reactants]

   7)      answer a

   equilibrium constant K=[CCl4][S2Cl2] /[CS2][Cl2]3

at equilibrium [CCl4]=0.15M [S2Cl2]=0.35M [CS2]=0.05M [Cl2]=0.25M
      equilibrium constant calculated from the given data K= 67.2

if the reactants and products concentrations are

[CCl4]=0.28M [S2Cl2]=0.28M [CS2]=0.14M [Cl2]=0.2M

From above concentrations, the calculated K=70

But, equilibrium constant should remain same even the concentrations are altered at similar conditions. Hence, the equilibrium shifts to left to reduce the concentration of products.

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