Calculate the concentrations of all species present (H2CO3, HCO3-, CO3 2-, H3O+,

Question

Calculate the concentrations of all species present (H2CO3, HCO3-, CO3 2-, H3O+, and OH-) in 0.018 M H2CO3.
Calculate the pH in 0.018 M H2CO3 (Kal = 4.3 × 10-7; Ka-5.6 × 10-11). Express your answer using two decimal places. pH- 4.06 Submit My Answers Give Up Correct Part B Calculate the concentrations of all species present (H2C03. HCO, CO2, H30' and OH-) in 0018 M H2COg Express your answers using two significant figures. Enter your answers numerically separated by commas. Submit My Answers Give Up

Explanation / Answer

Since the value of the second dissociation constant for HCO3- is very less, it means that the dissocation of bicarbonate ion to carbonate ion occurs to a negligible extent.

Hence we have only the following reaction taking place in the solution:

H2CO3 ---> H3O+ + HCO3-

So,

[H3O+] = [HCO3-] = 10-pH = 10-4.06 M

And.

[H2CO3] = 0.018-10-4.06 = 0.0179 M

[OH-] = (10-14)/[H3O+] = (10-14)/(10-4.06) = 1.148*10-10 M

[CO32-] = approximately zero

Hope this helps !

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