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I\'m not sure what to do with (a), for (b) I got 3.57 KJ/mol, an unfavorable pro

ID: 55962 • Letter: I

Question

I'm not sure what to do with (a), for (b) I got 3.57 KJ/mol, an unfavorable process, and for (c) I got -3.57 KJ/mol.

Any help is appreciated.

Here is the question in plain text in case there are issues with the image:

7. In living biological cells, the concentration of Na+ inside the cell is kept at a lower concentration than the concentration outside the cell because Na+ is actively transported out of the cell.
(a) Consider the following process at 37
°C and 1 atm:
1 mol NaCl (0.05M inside)
? 1 mol NaCl (0.20M outside).

Write an expression for the change in chemical potential of this process.

(b) Calculate ??. You may approximate the activities by concentrations in M. Will the reaction proceed spontaneously?

(c) Calculate ?? if the activity of NaCl inside is equal to the activity of NaCl outside the cell.

7. In living biological cells, the concentration of Na inside the cell is kept at a lower concentration than the concentration outside the cell because Na" is actively transported out of the cel (a) Consider the following process at 37 °C and 1 atm: 1 mol NaCl (0.05M inside) 1 mol NaCl (0.20M outside). Write an expression for the change in chemical potential of this process (b) Calculate . You may approximate the activities by concentrations in M. will the reaction proceed spontaneously? (c) Calculate if the activity of NaCl inside is equal to the activity of NaCl outside the cell.

Explanation / Answer

a. The expression for change in chemical potential is

For b, the change in chemical potential is -3.6 kj/ mol and is a favourable process

c. If the activity of NaCl outside and inside the cell are equal, then the change in chemical potential is 0 (zero)

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