Fe+CuSO4-->Cu+FeSO4 Calculate the theoretical yield of elemental copper metal in
ID: 560283 • Letter: F
Question
Fe+CuSO4-->Cu+FeSO4Calculate the theoretical yield of elemental copper metal in your reaction, in grams, if the other product of the reaction is iron (II) sulfate.
100 mL of 1M CuSO4 Fe: 2.02 g FeSO4: 2.747 g
I've worked out a few times and feel like my answer isn't correct Fe+CuSO4-->Cu+FeSO4
Calculate the theoretical yield of elemental copper metal in your reaction, in grams, if the other product of the reaction is iron (II) sulfate.
100 mL of 1M CuSO4 Fe: 2.02 g FeSO4: 2.747 g
I've worked out a few times and feel like my answer isn't correct Fe+CuSO4-->Cu+FeSO4
100 mL of 1M CuSO4 Fe: 2.02 g FeSO4: 2.747 g
I've worked out a few times and feel like my answer isn't correct
Explanation / Answer
reaction is Fe+CuSO4-->Cu+FeSO4.
in this reaction Fe and CuSO4 react in 1:1 molar ratio to form one mole Cu and one mole FeSO4.
100 mL of 1M CuSO4 = 0.100 * 1 = 0.100 mole.
2.02 gm Fe = 2.02 / 55.85 =0.0362 mole.
Fe is the limiting reactant.
so theoretical yield of Cu = 0.0362 * 63.5 = 2.297 gm
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.