determination of enthralled of neutralization between HCL and NaOH (C:17.55 J/C

Question

determination of enthralled of neutralization between HCL and NaOH (C:17.55 J/C Calorimetry (-Week 5.with my notes.. nsmart.com/flow binrunner.html?poa=0&isbn.12; 93353568 title-8deck dealearnsmart d-11622609&learnsmarturisw; we h earnsnartco mipasi assoasa Lab Notebook Determination of Enthalpy of Neutralization between HCI and NaOH (Cocl 17.55 J/°c). Calculation example Trial 1 Trial 2 Trial 3 Volume of HCI Initial temperature of HCI Volume of NaOH Initial temperature of NaOH Final solution temperature Moles of H Moles of OH Limiting reagent Heat transfer for solution 100 mL 100 mL 24 "C 100 mL 100 mL 25 C 24 C Da 100 mL 24 C 39 C mol mol 100 mL 24 C 25 C 40 °C 1 mol 1 mol 39 C mol Select Select Select kJ 945 AM

Explanation / Answer

Assuming that 'x1' L of 'y1' M HCl is used, and

'x2' L of 'y2' M NaOH is used.

So,

Moles of HCl used = Molarity*Volume = x1*y1

Moles of NaOH used = Molarity*Volume = x2*y2

If x1*y1 < x2*y2, then HCl is the limiting reagent, else NaOH is the limiting reagent.

Assuming that HCl is the limiting reagent:

Moles of H+ and OH- = x1*y1.

Change in temperature, dT = Final temp - Initial temp

Final solution volume = (x1 + x2) L

Assuming that density of this solution is the same as that of water, we have:

Mass of solution = Density*Volume = (x1 + x2) kg = (x1 + x2)*1000 grams

Heat generated by reaction = Heat absorbed by solution + Heat absorbed by calorimeter

dHrxn = Mass of solution*Cp*dT + Ccal*dT

Here, Cp = Heat capacity of solution, assumed to be equal to heat capacity of water = 4.18 J/(g.0C)

Putting values:

dHrxn = (x1 + x2)*1000*4.18*dT + 17.55*dT

Put the values to calculate dHrxn.

In order to calculate the heat of reaction in units of J/mol, divide dHrxn by x1*y1.

Hope this helps !

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