concentration of stock NaOH = 0.1228 M please use the number provided below to a

Question

concentration of stock NaOH = 0.1228 M

please use the number provided below to answer the questons. Thank you.

Volume of acetic acid used to make the buffer. Use the volumes above x 6 for the calculations in this part Volume of NaOH used to make the buffer. 46.35 ml Concentration of Stock Acetic Acid 0.1897 M (calculated in Part 1 and entered above) Show the NIE (for making the buffer) Show how you calculated the stoichiometric concentrations of HAc and Ac in the buffer (ICE Table and any calculations) Number of moles of NaOH used to make the buffer. Number of moles of Acetic Acid used to make the buffer What is the total volume after the Acetic Acid and NaOH have been mixed? Use volume in ml Stoichiometric concentration of HAc in buffer Stoichiometric concentration of Ac in buffer

Explanation / Answer

Net ionic equation

HA(aq) + OH-(aq) = H2O(l)+ A-(aq)

b)

mol of NaOH used --> MV = 0.1228*46.35*10^-3 = 0.00569178

c)

mol of Acetic acid used to make buffer ---> MV = 60*0.1897*10^-3 = 0.011382 mol of acid

d)

total V after mix --> 60+46.35 = 106.35 mL

e)

find HAc --> M1V1/(Vtotal) = 0.011382 /(106.35*10^-3) = 0.10702 M

f)

find Ac- in buffer --> (0.00569178)/(106.35*10^-3) = 0.0535 M

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