What pressure is exerted by 763.5 g of CH4 in a 0.730 L steel container at 188.0

Question

What pressure is exerted by 763.5 g of CH4 in a 0.730 L steel container at 188.0 K?

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Explanation / Answer

What pressure is exerted by 763.5 g of CH4 in a 0.730 L steel container at 188.0 K?

mol = mass/MW = 763.5/16 = 47.718

PV = nRT

P = nRT/V = (47.718)(0.082)(188)/(0.73) = 1007.699 atm

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