sTichhnoMETRY WORKSHEET Part 1t Composition 1) A red blood cell contains several
ID: 561992 • Letter: S
Question
sTichhnoMETRY WORKSHEET Part 1t Composition 1) A red blood cell contains several hundred thousands of hemoglobin molecules, which transport oxygen throughout the body. Determine the percent composition by mass) of hemoglobin: (CHsseNasO2oaS Fel 2) The percent composition of an organic chloride, which contains carbon, hydrogen, and chlorine, was found experimentally to be 32.18% C, 4.500% H and 63.32% a a) How many grams of carbon would be present in a 5.00g sample? b) How many grams of carbon would be present in a 100.0g sample? c) Determine the empirical formula of the organic chloride d) In a separate experiment, the molar mass of the organic chloride was determined to be around 220 g/mol. What is its molecular formula?Explanation / Answer
(C238H1166N812O203S2Fe)4
Find the number of each atom in one mole of (C238H1166N812O203S2Fe)4
C = 238 x 4 = 952
H = 1166 x 4 = 4664
N = 812 x 4 = 3248
O = 203 x 4 = 812
S =2 x 4 = 8
Fe = 1 x 4 = 4
Write down the atomic masses for the elements
C 12.01, H 1.008, N 14.007, O 15.999, S 32.065 and Fe 55.845
Next, determine how many grams of each element are present in one mole of (C238H1166N812O203S2Fe)4
Mass contribution of C= 952 x 12.01= 11433.52 g
Mass contribution of H = 4664 x 1.008 = 4701.312 g
Mass contribution of N = 3248 x 14.007 = 45494.736 g
Mass contribution of O = 812 x 15.999 = 12991.188 g
Mass contribution of S = 8 x 32.065 = 256.52 g
Mass contribution of Fe = 1 x55.845 = 55.845g
Find the total molecular mass of the molecule.
11433.52 g + 4701.312 g + 45494.736 g + 12991.188 g + 256.52 g + 55.845g = 74933.121 g
Now find the mass percentages of the elements
To find the mass percent of an element, divide the mass contribution of the element by the total molecular mass. Then multiply by 100% to be expressed as a percent.
Mass % C = 11433.52 g / 74933.121 g x 100 = 15.258
Mass % H = 4701.312 g /74933.121 g x 100 = 6.274
Mass % N = 45494.736 g / 74933.121 g x 100 = 60.713
Mass % O = 12991.188 g / 74933.121 g x 100 = 17.337
Mass % S = 256.52 g / 74933.121 g x 100 = 0.34
Mass % Fe = 55.845g / 74933.121 x 100 = 0.0745
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