i want to know why i have to divide 100g at the last step. why 100g ..? Chapter
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i want to know why i have to divide 100g at the last step. why 100g ..?
Chapter 3, Problem 135AE Bookmark Show all steps: ( ON The mass percent of cobalt in cyanocobalamin is 4.34%, it means 4.34 g Co is present in 100.0 g of cyanocobalamin The number of atoms of Co present in 1 mol of cyanocobalamin molecule is one, so for 1 mole of cyanocobalamin, 1 mol Co is present Then the moles of cyanocobalamin present in 4.36 g Co is: chen Ti Zr Hf r Rf 40 My Text l mol Co 4.34g Cox 58.93g Co l mol cyanocobalamin-116 0-2 mol 72 1 mol Co CHEM 11 f Comment 104 9th Edition View all solution Step 2 of 2 57 58 Then the molar mass of cyanocobalamin is obtained by dividing mass of cyanocobalamin by its La Ce moles: right 100.0 g 7.36x10 mol 89 90 Molar mass = Ac Th 1359 g/mol mula of the 141. A 0.755-g Hence the molar mass of cyanocobalamin is 1359 g/mol was heated c drous mine the 1 | | 0 Was this solution helpful? |Explanation / Answer
it is because the mole that you have calculated is for mass = 100g of cyanocobalamin.
And you have to calculate its molar mass so.
molar mass = mass / moles
that's why here you have to divide 100g at the last step.
if you satisfied with the solution please like it.. thanks.
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