The following reaction is run, beginning with 10 atm of NO. At equilbrium, it is
ID: 563172 • Letter: T
Question
The following reaction is run, beginning with 10 atm of NO. At equilbrium, it is found that there are 2 atm of NO remaining.
- What is the value of Kp for this Reaction? 2NO(g) >< N2(g) + O2(g)
- If this reaction is repeated at the same temperature but with the following initial partial pressures, what is the value of Q? Which way will the reaction proceed?
PN2= 8 atm, PO2 = 10 atm, PNO = 5 atm
- if the experiment is repeated again at the same temperature, but the scientists begins with 16 atm of NO and no O2 no N2. Given the Kp that you solved for previously, what will be the equilibrium partial pressure of NO, O2, and N2?
- The experiment is repeated yet again with 10 atm of O2, 10 atm of N2, and no NO,. What will be the equilibrium partial pressure of NO?
Explanation / Answer
2NO(g) >< N2(g) + O2(g), let P= partial pressure
PNO= partial pressure of NO= 10 atm before reaction, let x = pressure of O2 at equilibrium= pressure of N2 at equilibrium, at equilibrium, PNO= 10-2x, PN2= PO2= x
but given PNO= 10-2x= 2, 2x=8 and x=4
hence at equilibrium, PNO= 2 atm, PN2= PO2= 4, K= PN2*PO2/ (PNO)2= 4*4/4= 4
for the given data, Q= 10*8/ 5*5 = 3.2<K, the reaction proceeds in the forward direction.
3. since there is no O2, Q= 0<K so forward reaction takes place
let x= partial pressure of O2 at equilibrium, at equilibrium, PO2=16-2x, PN2= PO2=x
K= x2/(16-2x)2= 4, Taking square root, x/(16-2x)= 2 ,x = 2*(16-2x), 5x= 32, x= 32/4= 6.4
So at equilibrium, PN2=PO2= 6.4 atm and PNO= 16-2*6.4= 3.2 atm
4. for this case also, Q= infinity, there is no NO. so reverse reaction takes place. let x= drop in pressure of N2 or O2 to reach equilibrium, at equilibrium, PN2= PO2= 10-x and PNO=2x
K= 4= (10-x)2/(2x)2, Taking square root, (10-x)/ 2x= 2 or 10-x= 4x, x= 2
so at equilibrium, PN2=PO2= 10-2= 8 and PNO= 4 atm
- The experiment is repeated yet again with 10 atm of O2, 10 atm of N2, and no NO,. What will be the equilibrium partial pressure of NO?
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