calculate the osmotic pressure of a split containing 16.70 mg of hemoglobin in 1

Question

calculate the osmotic pressure of a split containing 16.70 mg of hemoglobin in 15.5 mL of solution at 24 degrees Celsius. The molar mass of hemoglobin is 6.5•10^4 g/mol ercise 12.58 with feedback Constants 1 Period You may want to reference (Pages 497-505) section 12 6 while completing this problem PartA calculate the osmotic pressure of a soldon contar-1670 ofhemoglobin in 155 mLofsolton at 24 ·C The molr mass of hemog obn is 0.5 x 10. Express your answer in atmospheres II-1 X incorrect; Try Again; attempts remaining e to search oen @ 8 9

Explanation / Answer

Osmatic pressure = C * R * T

where, C = concentration

R = Gas constant

T = temperature = 24 + 273 = 297 K

C = number of moles / volume of solutoin in L

number of moles of hemoglobin = mass / molar mass

number of moles of hemoglobin = 0.0167 g / 6.5*10^4 g/mol = 0.00257*10^-4 mol

C = 0.00257*10^-4 mol / 0.0155 L = 0.166 * 10^-4 M

osmatic pressure =  (0.166*10^-4 )* 0.0821 * 297 = 4.05*10^-4 atm

Therefore, osmatic pressure = 4.05*10^-4 atm

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