Complete a balanced redox reaction from part A in your report. [1,2,3,1 S4O6 2-,

Question

Complete a balanced redox reaction from part A in your report.

[1,2,3,1 S4O6 2-, 2 S4O36 2-, 3 S4O6 2-] Fe(CN)63- + [1,2,3,1 S4O6 2-,2 S4O36 2-,3 S4O6 2-] S2O32-   [1,2,3,1 S4O6 2-,2 S4O36 2-,3 S4O6 2-] Fe(CN)64- + [1,2,3,1 S4O6 2-,2 S4O36 2-,3 S4O6 2-]

The bracket numbers are the answer choices I have to choice from.

QUESTION 2

According to the instructions, 1.5 g of KI is added to a solution containing 0.60 g of K3Fe(CN)6, and the following reaction occurs:

            2 Fe(CN)63- + 2 I- 2 Fe(CN)64- + I2.

Which reagent is in excess?

Fe(CN)63-

I-

I2

Fe(CN)64-

1 points   

QUESTION 3

Match standard solution and standardizing a solution with their correct definitaions.

standard solution

standardizing a solution

is a solution containing a precisely known concentration of an element or a substance

is the process of determining the exact concentration (molarity) of a solution.

is a chemical reaction in which an acid and a base react quantitatively with each other.

QUESTION 4

According to the instructions, 1.5 g of KI is added to a solution containing 0.60 g of K3Fe(CN)6, and the following reaction occurs:

            2 Fe(CN)63- + 2 I- 2 Fe(CN)64- + I2.

Calculate the number of mmoles (1 mmole = 1 x 10-3 moles) of I2 formed from these amounts of reagents.

Fe(CN)63-

I-

I2

Fe(CN)64-

Explanation / Answer

Reaction

2. According to the given reaction,

moles Fe(CN)6^3- = 0.6 g/212 g/mol = 0.003 mol

moles I- = 1.5 g/166 g/mol = 0.009 mol

Since moles of I- is in excess,

the reagent in excess would be,

I-

---

3. Matching the two columns

Standard solution : A. is a solution containing a precisely known concentration of an element or substance

Standarizing a solution : B. is a process of determining the exact concentration (molarity) of a solution

--

4. According to the given reaction,

moles Fe(CN)6^3- = 0.6 g/212 g/mol = 0.003 mol

moles I- = 1.5 g/166 g/mol = 0.009 mol

here, Fe(CN)6^3- is the limitjng reactant

therefore,

moles of I2 produced = 0.003 mole/2 = 0.0015 mole

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.