14. The \"filmstrip\" represents five molecular-level scenes of a gaseous mixtur

Question

14. The "filmstrip" represents five molecular-level scenes of a gaseous mixture at 25 C as it reaches equilibrium over time. Let the dark circles represent X and the white circles represent Y. X2(g) + Y2(g)2XYg). 800 a) Write the equilibrium constant expression for the reaction, b) If each particle represents 0.100 mol of particles, calculate Q for each scene, A-E d) If K>1, is time progressing to the right (A to E) or to the left (E to A)? Explain your choice d) Calculate K at this temperature.

Explanation / Answer

LEt's write the overall reaction again:

X2(g) + Y2(g) <---------> 2XY(g)

The equilibrium constant Kc would be:

Kc = [XY]2 / [X2] [Y2]

b) Let's do this for all scenes:

A: in this we only have molecules of X and Y, and no XY formed so:

Qa = 02 / 0.8*0.8 = 0

B: We see some particles of the product XY so:

Qb = (4*0.1)2 / (2*0.1)(2*0.1) = 4

C, D, and E they all have the same numbers of molecules so:

Qc = Qd = Qe = (6*0.1)2 / (0.1)(0.1) = 36

c) If K>1 or in this case K>Q then the reaction will proceed towards the product side. In scene A, Q<1 therefore, the reaction will go towards the reactants. In the rest of the scene Q>1 so the reaction will go towards the product side.

d) The exercise does not provide the temperature, so we can't calculate k at this moment.

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