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Lab 7: Rates of Chemical Reactions,I The lodination of Acetone Section Advance S

ID: 567665 • Letter: L

Question

Lab 7: Rates of Chemical Reactions,I The lodination of Acetone Section Advance Study Assignment: The lodination of Acetone I. In a reaction involving the iodination of acetone, the following volumes wcre used to make up the reaction 10 ml. 4.0 M acetome+10 ml. 1.0 M HCI+10 mL.0.0050 M I,+20 mL. H,O How mamy moles of acctone were in the reaction misture? Recall that, for a compoeent A, no. moles a. A-MxV, where M,is the molarity of A and V is the volume in liters of the solution of A that was used. moles acetone h What was the molarity of acctone in the reaction mixhure? The volume of the mixture was 50 ml 0.050 L, and the number of moles of acetone was found in Part (a). Again, soln. in M acctone c How could you double the molarity of the acetone in the reaction mixture, keeping the total volume at 50 mL. and keeping the same concentrations of H' ion and I, as in the original mixture? 2. Using the reaction mixture in Problem 1, a student found that it took 230 seconds for the color of the L, to disappear What was the rate of the reaction? Hint: First find the initial concentration of L, in the reaction mixture, Then use Equation 5. rate h. Given the rate from Part (a), and the initial concentrations of acetone, Ht ion, and I, in the reaction mixture, write Equation 3 as it would apply to the mixture rale . What are the unknowns that remain in the equation in Part (b)? (continued on following page

Explanation / Answer

1 a. The initial no. of millimoles acetone = 10 mL * 4 mmol/mL = 40 mmol

Therefore, the no. of moles of acetone in the reaction mixture = 40*10-3 mol = 4*10-2 mol

b. The total volume = (10+10+10+20) mL = 50 mL = 50*10-3 L = 5*10-2 L

Therefore, the concentration of acetone in the reaction mixture = no. of mol of acetone/total volume

= 4*10-2 mol/5*10-2 L

= 0.8 M

c. By doubling the volume of 4 M acetone solution (i.e. 20 mL) and by halving the volume of water (i.e. 10 mL)

Now, the concentration of acetone = 20*4/50 = 1.6 M