You perform the experiment and find your average atomic mass to be 54.59. Based

Question

You perform the experiment and find your average atomic mass to be 54.59. Based off this, you assume your unknown volatile liquid is acetone. Use the table below to find the molar mass of acetone. What is the percent error in your measurement? Recall the percent error equation, given in lab 2, reports the answer as arn absolute value. Possible Unknown Methanol Ethanol Acetone Molar Mass (g/mol) 32.04 46.07 58.08 Chemical Formula CH40 C2H6O C3H60 | Percent error- How many significant figures should you have reported your percent error to? Select an answer significant figures

Explanation / Answer

Percent error = (58.08 - 54.59) * 100 / 58.08 = 6.009 %

During substraction there two decimal place.

6.00 have three significant figures.

This is using BODMAS rule and considering substraction multiplication rule of sig. fig calculation.

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