Print Calculator A Periodic Table - Question 7 of 36 Incorrect IncorrectIncorrec
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Print Calculator A Periodic Table - Question 7 of 36 Incorrect IncorrectIncorrect Av Map General Chemistry 4th Edition . niversity Science Books presented by Sapling Learning Po Cryolite, Na3AlF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide Balance the equation lip: It you need to clear your work and reset the equation, click the button that looks like two red arrows Al,o, s)+6Na12H 2NaAIF, + 9H.O Po If 14.8 kilograms of Al203(s), 60.4 kilograms of NaOH(), and 60.4 kilograms of HF(g) react completely, how many kilograms of cryolite will be produced? Yo Yo Number 1 kg Na, AIF Yo Yo ar at 290 × 10-3 Which reactants will be in excess? What is the total mass of the excess reactants left over after the reaction is complete? Number NaOH HF 12.79873653kgExplanation / Answer
moles of Al2O3 = mass / molar mass
= 14.8 x 10^3 / 101.96
= 145.16
NaOH moles = 60.4 x 10^3 / 40 = 1510
moles of HF = 60.4 x 10^3 / 20 = 3020
balanced equation :
Al2O3 + 6 NaOH + `12 HF -------------------> 2 Na3AlF6 + 9 H2O
1 6 12 2
145.16 1510 3020
limiting reagent is Al2O3
excess reagents NaOH , HF
mole of Na3AlF6 formed = 2 x 145.16 / 1
= 290.32
mass of Na3AlF6 = 290.32 x 209.94
= 60950 g
= 61.0 kg
mass of Na3AlF6 formed = 61.0 kg
NaOH remaining = 1510 - 6 x 145.16
= 639.04
mass of NaOH = 639.04 x 40
= 25562 g
mass of NaOH = 25.56 kg
moles of HF remains =3020 - 12 x 145.16
= 1278
mass of HF = 1278 x 20
= 25562 g
= 25.56 kg
mass of excess reagent left = 25.56 + 25.56
= 51.1 kg
mass of excess reagent left = 51.1 kg
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