A chemist working as a safety inspector finds an unmarked bottle in a lab cabine

Question

A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store bottles of dimethyl sulfoxide, tetrahydrofuran, methyl acetate, chloroform, and diethylamine The chemist plans to try to identify the unknown liquid by measuring the density and comparing to known densities. First, from her collection of Material Safety Data Sheets (MSDS), the chemist finds the following information: density dimethyl sulfoxide 1.1 g em tetrahydrofuran 0.89 g cm methyl acetate 0.93 g em 1.5 g cm diethylamine 0.71 gcm liquid 3 chloroform Next, the chemist measures the volume of the unknown liquld as 0.808 L and the mass of the unknown liquid as 570. g. Calculate the density of the liquid. Round your answer to 3 significant digits Given the data above, is it possible to identify es the liquid? dimethyl sulfoxide methyl acetate chiloroform diethylamine If it is possible to identify the liquld, do so.

Explanation / Answer

1) Density of liquid : Density is calculated using following equation,

Density = Mass (g) / Volume (mL)

= 570 g / 808 mL

( 0.808 litre = 0.808 x 1000 = 808 mL)

= 0.705 g/cm3 = 70.5 x 10-2 g/cm3.

2) Yes. From obtained density it is possible to find unkown liquid.

3) The calculated density of liquid is 0.705 g/cm3 which is nearer or comparible with the density of diethylamine

( 0.71g/cm3) . Therefore unkown liquid is diethylamine.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.