sign Layout 39) Define an Arrhenius acid. 39) A) produces OH ions in aqueous sol

Question

sign Layout 39) Define an Arrhenius acid. 39) A) produces OH ions in aqueous solution B) an electron pair receiver C) accepts Ht ions D) an electron pair donor E) produces H+ ions in aqueous solution 40) Define an Arrhenius base. 40) A) an electron pair receiver B) produces H+ ions in aqueous solution C) accepts Ht ions D) an electron pair donor E) produces Oft sons in aqueous solution 41) The titration of 25.0 mL of an unknown concentration H2504 solution requires 83 6 mL of 012 M 41) LiOH solution. What is the concentration of the H25O4 solution (in M)? D) 025 M A) 0.20 M B) 0.10 M C) 040 M E) 0.36 M 42) Choose the reaction that represents the combustion of CeH1202 42) A) C6H12024) * 802(g) 6 CO2(g) + 6 H2O(g) B) 6 C(s) + 6 H2ig) + O2(g) C6H12O2(1) E) None of the above represents the combustion of CoHi202

Explanation / Answer

39) Arrhenius acid produces H+ ions in aquesous solution. option E is correct

40) Arrhenius base produces OH- ions in aquesous solution. option E is correct

41)

Balanced equation between H2SO4 and LiOH

H2SO4 + 2LiOH -------> Li2SO4 + 2H2O

Number of moles of LiOH = molarity * volume of solution in L

Number of moles of LiOH = 0.12 * 0.0836 = 0.0100 mole

from the balanced equation we can say that

2 mole of LiOH requires 1 mole of H2SO4 so

0.0100 mole of LiOH will require 0.005 mole of H2SO4

Molarity of H2SO4 = number of moles of H2SO4 / volume of solution in L

Molarity of H2SO4 = 0.0100 / 0.025 = 0.40 M

Therefore, molarity of unknown solution is 0.40 M

option C is correct

42) The combustion of C6H12O6 is represented by option A.

C6H12O6 + 8 O2 -----> 6 CO2 + 6 H2O

combustion of C6H12O6 means the reaction of C6H12O6 with O2 to produces CO2 and H2O.

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