QUESTION 1 4 567 8 9 10 11 12 13 16 VItI B He 5 6 78 910 B C N O F Ne Li Be 6.94

Question

QUESTION 1 4 567 8 9 10 11 12 13 16 VItI B He 5 6 78 910 B C N O F Ne Li Be 6.944 9.012 1112 Na Me 22.99 24.30 10.81 12.01 14.01 16.00 19.00 20.18 1314 1516 17 18 Al Si P S C Ar 27.00 28.09 30.97 32.06 35.45 39.95 19 20 21 22 23 24 25 262728 29 303132 33 3435 36 K Ca Se Ti V r Mn F Co Ni Cu Zn Ga Ge As SeBr Kr 39.10 40.08 44.96 47.87 50.94 s2.00 54.94 ss.84 893 58.69 63.5s 65.39 69.72 7264 74.92 78.96 79.90 83.30o 87 38 39 41 42 434445 46 47 4950152 53s4 Rb r Y Zr Nb Mo Te Ru Rh Pd Ag Cd In Sn Sb TeXe 85.47 87.62 88.91 91.22 92.91 95.94 (98) 1011 102.9 1064 107.9 1124 1148 118.7 1218 127.6 1267 131.3 72 73 74 75 76 78 79 80 81 82 8384 85 86 Pt Au He TPb Bi Po At Rn 178.5 1809 183.8 1862 10.2 192.2 1951 1970 2006 204.4 2072 209.0 (209) (210)(222) 55 56 Cs BaHf Ta W Re Os r 132.9 137.3 87 88 1223).11(226). (261) (262) t2G6) (264) (269) (26a1 (271) (272) E277) (284) (285) (288) (289) (294) (294) 57 58 59 60 62 63 64 65 66 67 68 69 7071 La Ce Pr Nd Pm Sm Eu Gd Tb Dy o Er Tm Yb Lu 138.8 140.1 140.9 144.2 (145) 1504 152.0 157.2 158.9 162.5 164.9 167.3 168.9 173.0 175.0 Lanthanides 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 Ac Th Pa U Np Pu Am Cm Bk C Es Fm Md No Lr (227) 232.0 2310 238.0 (237) (244) (243 (247) (27) (251) (252) 257) (258) (29(262) "Actinides What is the electronic configuration of 15P?

Explanation / Answer

Number of electron in P = 15
Electronic configuration is 1s2 2s2 2p6 3s2 3p3

Noble gas having lesser electron than P and closest to it is Neon (Ne)
Number of electron in Ne = 10
electronic configuration of Ne is: 1s2 2s2 2p6

So, electronic configuration of P in noble gas form is: [Ne] 3s2 3p3
Answer: [Ne] 3s2 3p3

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