Jump to... Table Question 16 of 27 Map Sapling Learning When two volatile liquid

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Jump to... Table Question 16 of 27 Map Sapling Learning When two volatile liquids (X and Y) are mixed, the solution process involves 1. breaking the intermolecular X--X and Y-Y attractions, and Complete this table describing how the relative strengths of these attractive forces affect vapor pressure and enthalpy of solution. Raoult's law Strength of the attractive forces Hsoln deviations X--X, Y..-Y, and X.Y are equal negative X--Y is strongest X--Y is weakest positive negative zero There is a hint a ew the hint by clicking on the ottom divider bar. Click on the vider bar again to hide the hint. Exit Previous Give Up&View; Solution Check Answer Next

Explanation / Answer

1)

Here all the bonds have same strength

So, there will not be deviation

Answer: Zero, Zero

2)

Here the bond that formed as a result of mixing is stronger than the bond initially present

This implies negative deviation and hence delta H will be negative

Answer: negative, Negative

3)

Here the bond that formed as a result of mixing is weaker than the bond initially present

This implies positive deviation and hence delta H will be positive

Answer: positive, positive

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