Complete the repeat pipetting exercjse and get checked off From the dilution ser

Question

Complete the repeat pipetting exercjse and get checked off From the dilution series you set up today: 1) What is the dilution factor of dye in the 4 tube of the 1:10 dilution series? 1000 started w/1: 10 150AL 2 200Ji ! 10 190 100 (dye was undiluted or "neat" in well 1) nglm 2) What is the concentration of dye in 7. tube of the l :2 series? (dye was 10mg/ml in well l) ½.4.tu 3) What is the starting concentration of dye in your unknown tube? Unknown Number2Concentration GRAPH YOUR STANDARD CURVE. SHOW YOUR WORK General questions: SHOW YOUR WORK 4) What is the final dilution if you mix 1 ml of a 1:2 dilution with 2 ml of diluent? In a tube containing 1 ml of a 1:4 dilution of substance A, and 1 ml of a 1:16 dilution of substance B: What is the final dilution of substance A? What is the final dilution of substance B?

Explanation / Answer

1) Using ; final dilution factor = dilution factor 1*dilution factor 2*dilution factor 3* dilution factor4 =1*1/10*1/10*1/10

=1/1000

2) Similarly as first part dilution factor for this will be 1*1/2*1/2*1/2*1/2*1/2*1/2(here dilution is 1/2 ,in first part it was 1/10 that's why 1/2) =1/64

Using C1*V1 = C2*V2 , we get

10*1=C2*64

C2= 10/64mg/ml

3) Insufficient information because neither the final concentration nor the dilution factor is given.

4)In 1ml of 1:2 dilution ,solute will be 0.5 ml (because in 2 parts 1 part is solute ) .Adding this to 2ml diluent will result in total volume of 3ml and hence final dilution will be 0.5/3=1:6

5)For A : in 1ml 1/4 ml A is present.

For B : in 1ml 1/16ml B is present.

so. after mixing the two tubes , final volume will be 2ml.

so, now final diilution of A will be (1/4)/2 = 1/8 = 1:8

and for B final dilution will be (1/16)/2 = 1/32 = 1:32

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