please I need full answer for self-test 7.3 MPLE 7.3 Identifying isomers from ch
ID: 573018 • Letter: P
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please I need full answer for self-test 7.3
MPLE 7.3 Identifying isomers from chemical evidence EXA he reactions indicated in Fig. 74 to show how the cis and trans geometries of a pair of platinum complexes may be assigned. Answer The cis diamminedichlorido isomer reacts with Ag,0 to lose Cl-, and the product adds one oxalato dianion (C,O) at adjacent positions. The trans isomer loses Cl, but the product cannot displace the | two OH- ligands with only one C.anion. A reasonable explanation is that the C20, anion cannot reach across the square plane to bridge two trans positions. This conclusion is supported by Xray crystallography Selftest 73 The two square- planar isomers of [PtBrCI(PR,),] (where PR, is a trialkylphosphine) have different 3 PNMR spectra (Fig. 7.5). For the sake of this exercise, we ignore coupling to Pt (at 33 per cent abundance). One isomer (A) shows a single 3"P resonance; the other (B) shows two 3"P resonances, each of which is split into a doublet by the second 3 P nucleus. Which isomer is cis and which is trans?Explanation / Answer
A isomer should be trans, because in trans both phosphorus atom are in same environment, the bond angle between P(PR)3 -Pt-Cl is 90 for both phosphorus, similarly both phosphorus are in same environment to bromine also
B isomer should be cis, because in cis isomer both phosphorus are in different environments one phosphorus group is 90 degree to Cl and other phosphorus is 180 to chlorine, so both phosphorus show different chemical shift. The phosphorus signal ger couple with each other and get split into two
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