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owLV2 | Online teachin + O |sjc.cengagenow.com/ilrn/takeAssign lentActivity.do?locato assignment-take8takeAssignmentsessionLocator-assignment-take Chapter 10: Mastery ea) Use the References to access im portant values if needed fo r this question. 1. Compare Absolute Entropies 2. Predict the Sign of AS 3. ASsurToundings 4. Standard Entropy of Reaction pts 1 pts For the reaction 1 pts 2req 1 pts 2req 1 pts 2req 1 pts 2req 7 AG: Enthalpy. Entropy and Temper. .1 pts @) 8. AG: Calculate Temperature Limit 1 pts 2req 2H2O02H2(g) +O2(g) G° would be negative at temperatures (above, below) K. 6. AG: Predict Signs Enter above or below In the first box and enter the temperature in the second box. Assume that Ho and S° are constant. Submit Answer Retry Entire Group 8 more group attempts remaining Question of Refining Met... 1 pts 2req 10. AG from Free Energies of Form 1 pts 2req

Explanation / Answer

deltaH = 572.0 KJ

deltaS = 327 J/K

= 0.327 KJ/K

we have below equation to be used:

deltaG = deltaH - T*deltaS

for reaction to be spontaneous, deltaG should be negative

that is deltaG<0

since deltaG = deltaH - T*deltaS

so, deltaH - T*deltaS < 0

572.0- T *0.327 < 0

T *0.327 > 572.0

T > 1749 K

Answer: above 1749 K

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