Google Chrome Secure https//session.masteringchemistry Chapter 3: Stoichiometry

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Google Chrome Secure https//session.masteringchemistry Chapter 3: Stoichiometry ± Percent Yield h.com/myct/itemView2assignmentProblemID-962796018xoffset-next The Haber Bosch process is a very important ndustrial process. in the Haber-Bosch process hydrogen gas reacts with itogen gas to produce ammonia according to the equation Part A The anmona produced in the Haber Bosch process has a wide range of unes, from tertlizer to pharmaceubicals Howerver, the production of ammonsa is diicut hose predicted from the chemical equation What is the theonetical yield in grams for this neaction under the given conditions? Express your answer to three significant figures and include the appropriate units View Available Hins) resulting in lower yields than Value Units Submi Part B What the percent yeld for this reactor, undete gven condtons? Express your answer to three significant figures and include the appropriate units View Awailiable Hints) Value Units Provido Feedback

Explanation / Answer

Ans :

Part A :

Number of moles = given mass / molar mass

Number of moles of H2 = 1.69 / 2.016 = 0.838 mol

Number of moles of N2 = 9.77 / 28.0134 = 0.349 mol

1 mol of N2 requires 3 mol of H2 to produce 2 mol of NH3 according to the balanced reaction

So 0.349 mol of N2 will require : 0.349 x 3 = 1.047 mol of H2

H2 is the limiting reagent

3 mol H2 makes 2 mol of NH3

so 0.838 mol of H2 will make ( 0.838 x 2) / 3 = 0.559 mol of NH3

Theoretical yield of NH3 = 0.559 x 17.031

= 9.52 g

Part B :

Percent yield = ( actual yield / theoretical yield) x 100

= ( 1.16 / 9.52) x 100

= 12.2 %

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