162 Experiment 20 Rates Chemical Rouctora, L The lodnalon ce Acetone 3. A second
ID: 574587 • Letter: 1
Question
162 Experiment 20 Rates Chemical Rouctora, L The lodnalon ce Acetone 3. A second reaction mixture was made up in the following way: 5 mL 4.0 M acetone+20 mL. 1.0M HCI+ 10 mL. 0.0050 MI,15mL. Ho a. What were the initial concentrations of acetone, H' ion, and I, in the reaction mixture? moles acetone] M: (H'1 b. It took 250 seconds for the I, color to disappear from the reaction mixture when it occurred at the same temperature as the reaction in Problem 2. What was the rate of the reaction? rate-2x14-Mare Write Equation 3 as it would apply to the sccond reaction mixture 3asil wouldapplytothesoor dreaction mixture: rate Divide the equation in Part (b) by the equation in Problem 2(b). The resulting equation should have the ratio of the two rates on the left side and a ratio of H' concentrations raised to the p power on the right. Write the resulting equation and solve for the value of p, the order of the reaction with respeet to H·Round off the value of p to the nearest integer.) c. 4. A third reaction mixture was made up in the following way: 5 mL. 4.0 M acetone + 20 mL. 1.0 M HCI+5 ml.0.0050 MI2+20 mL. H.O If the reaction is zero order in Is, how long would it take for the l; color to disappear at the temperature of the reaction mixture in Problem 3? 12 rate secondsExplanation / Answer
Your results from 3 a and 3 b are correct
The rate expression will be
rate=k(acetone)m(I2)n(H+)p
rate = k * (0.4)m*(0.001)n*(0.4)p
The statement mentions a equation from a part 2b, this has not been provided.
4. The total volume is 5 + 20 + 5 + 20 = 50 ml, if you look close to the reaction in step 3 the volume and the molarites for acetone and H+ are the same rate expression will be
rate = k * (0.4)m*(0.4)p , if it is zero order in I2 then it wont be in our equation, this equation is similar to the previous rate equation in step 3, since order is zero in I2 the rate equation will be the same, therefore the time will be the time in step 3
time = 250 seconds
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