A chemist wishes to make a solution using 3.81 g of CoCl, in which the total con

Question

A chemist wishes to make a solution using 3.81 g of CoCl, in which the total concentration of Cl ions is equal to 0.233 mol/L. What must the final volume of the solution be? Let's start by understanding the relationship between(CoCl,land[Crl. In order for [CI-1 to equal 0.233 M what must (CoCl,l equal? Part 2 (0.3 point) Molarity is defined as moles solute 3.81 g of CoCl? See Hint we need to calculate the moles of CoCi, How many moles of CoCl, are equivalent to moles CoCl See Hint Part 3 (0.3 point) Finally we can calculate the final volume of the solution What final volume will produce a solution inwhich(Cr]-0233 Musing 3,81 g of CoC? K 02/24> re to search 0

Explanation / Answer

CoCl3 ----> Co 3+ + 3 Cl-

1 mole of CoCl3 contains 3 moles of Cl-

Given [Cl-] = 0.233 M

So [CoCl3]= [Cl-]/3= 0.233/3=0.078M

Molar mass of CoCl3 is 165.3 g/ mol

Number of moles,n= mass/ molar mass

n= 3.81 g/ 165.3 g/ mol

n= 0.023 moles

Molarity,M = number of moles/ volume in L

So volume of solution,V = number of moles/ molarity

= 0.023 mol / 0.078 M

= 0.295 L

= 295 mL

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