avogadro\'s constant in gas equations - THEY ARE three different questions. Asap

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avogadro's constant in gas equations - THEY ARE three different questions.  

Asaple of ga. costa " 0.1500 mol of Ml3(g) and 0.187S mel o02(g) aed soaps“ a alua. of 11.6 L. Tha Lollow4 aaetea takes place cellowing Caleslane ritet einme of the smpl" er the reamer, takes place, ,,senning that ite tempermre md-he presstre remain oomstam 0.1980 elo Caicult, the TOhrme of The sample after terexmon take, plac®, 353mmmgdtar the-eneperatw·and the pressrre main constant As mple of gas con ams 0.2000 mol of CH4(g) and 0.4000 mel of 0 md oorweexelume of 23,1 L The folle nng reaction takes place Calculate hhemr the eactia takas plae, umin that t beaperatore and thereu rcoatant

Explanation / Answer

1.

4 NH3 (g) + 5 O2 (g) --------> 4 NO (g) + 6 H2O (g)

From the balanced equation,

4 mol of NH3 needs 5 mol of O2

then,

0.1500 mol of NH3 needs 0.1500 * 5 / 4 = 0.1875 mol

SO, both will consume exactly.

Now from the balanced equation,

4 mol of NH3 forms 4 mol of NO and 6 mol of H2O

Then,

0.1500 mol of NH3 forms 0.1500 mol of NO and 0.1500 * 6 / 4 = 0.225 mol of H2O

Therefore,
Total number of moles of products = 0.1500 + 0.2250 = 0.3750 mol

According to Avagadro's law,

at constant temperature and pressure equal volumes of gases can have equal number moles of molecules.

V 1 / n1 = V2 / n2

11.6 / (0.1500 + 0.1875) = V2 / ( 0.3750)

V2 = 12.9 L

2.

Intial number of moles reactants = 0.1900 + 0.5700 = 0.7600 mol

From the balanced equation,

1 mol of N2 can form 2 mol of NH3

then

0.1900 mol of N2 can form 0.3800 mol of NH3

According to Avagadro's law,

V1 / n1 = V2 / n2

34.5 / 0.7600 = V2 / 0.3800

V2 = 17.25 L

3.

CH4 (g) + 2 O2 (g) ---------> CO2 (g) + 2 H2O (g)

Intial moles of reactants = 0.2000 + 0.4000 = 0.6000 mol

From the balanced equation,

1 mol of CH4 forms 1 mol of CO2 and 2 mol of H2O

then,

0.2000 mol of CH4 forms 0.2000 mol of CO2 and 0.4000 mol of H2O

SO, total number of moles of products formed = 0.2000 + 0.4000 = 0.6000 mol

According to Avagadro's law,

V1 / n1 = V2 / n2

23.1 / 0.6000 = V2 / 0.6000

V2 = 23.1 L

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