6 In the E: elimination of H and Br from 2-bromo-2-methyl- butane (sown below) w

Question

6 In the E: elimination of H and Br from 2-bromo-2-methyl- butane (sown below) with potassium hydroxide, which pH 28. What are the major product(s) likely to be obtained from the following reaction? a) I, by predominantly SH2 b) II, by predominanty S c) An equimolar mix of I and II, by predominantly Sw d) im, by substitution of the alkyl group, rather than subsitution of the chloro group 27. Which reagent would you use to carry out the following)Actualy, none o as major products, because elimination will predominate, leading to the formation of an alkene. elimination reaction Arrange the following cations in order of stablity from most to least stable: 29. a) HCUheat b) NHs c) CHiCO Na /CH COOH, heat d) CHCHO. Na.CHGHz H, heat B. Longer answer problems -42 points Ho 30. (4 points) The molecule at the right is glucose, one of the saccharides in ordinary table sugar which is probably the single most abundant pure organic compound in the world and the most widely known to non-chemists. Circle each tetrahedral stereocenter OH How many stereoisomers are possible for this molecule? 31. Consider the following compounds I -V: a) (1 pt) How many stereocenters in each molecule? b) (3 pts) What is the relationship between the following IV I & I c) (2 pts) Which compounds are: optically active? meso and optically inactive? d) (3 pts) Draw the mirror image of isomer III Would this mirror image be superimposable on any other isomer? If so, which one? Would III and its mirror image be optically active or inactive? Explain.

Explanation / Answer

Just 1 question at a time please =)

For the first question you will get a product according to zaitzevs rule which says that the most substituted alkene will be the mainly produced, so to answer this the Carbon that will lose and hydrogen will be the one with the less number of hydrogen so the hydrogen that will be abstracted will be the one that is to the right of the central carbon

answer is Hc or option C

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