(iii) 2.5 atm. = 1899999 87 mmHg 3. Calculate each of the following (a) a gas wi
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Question
(iii) 2.5 atm. = 1899999 87 mmHg 3. Calculate each of the following (a) a gas with pressure of 740 mmHg and volume of 2.5 liters is compressed to a new pressure of 0.5 atm. What is the new volume of the gas? (b) an oxygen gas container has a volume of 3.0 liters and a pressure of 2.5 atnm If the expands to a new volume of 5.5 liters, what will be the new pressure? (c) a nitrogen tank has a volume of 2.5 liters at a temperature of 50 C. What is the new volume of the gas if the temperature is raised to 150 F (d) an oxygen canister has a volume of 5.5 Liters at a temperature of 50 C. What is the temperature if the canister expands to 8.2 liters? . Write the balanced equation for FIVE examples of reactions invalvine aoeas Name ALL t Zn(s (iv)Explanation / Answer
3.
a) Initial final
P1=740mm P2= 0.5 atm
=0.974 atm
V1= 2.5L V2 = ?
according to boyles law
P1V1 = P2V2
0.974 x 2.5 = 0.5 x V2
V2= 4.87 L
New volume of the gas = 4.87 L
b) Initial final
P1= 2.5 atm P2=
V1= 3.0 L V2 = 5.5L
P1V1= P2V2
2.5 x 3.0 = P2 x 5.5
P2=1.36 atm
New pressure of gas = 1.36 atm
c) T1= 50C = 50+273 = 323K
T1= 150F= 65.56C = 65.56+273 = 338.56K
Initial final
V1= 2.5L V2=
T1=323K T2= 338.56K
According to Gay-lussacs las
V1/T1 = V2/T2
2.5/323 = V2/338.56
V2= 2.62L
New volume = 2.62L
d) Initial Final
V1=5.5L V2=8.2L
T1= 50C=50+273=323K T2=
V1/T1 = V2/T2
5.5/323 = 8.2/T2
T2=481.56K
New temperatuture = T2= 481.6K
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