EXPERIMENT 4 PRE-LAB QUESTIONS (20 points) Chemical Kinetics Refer to the propos

Question

EXPERIMENT 4 PRE-LAB QUESTIONS (20 points) Chemical Kinetics Refer to the proposed mechanism for the iodination of cvclobexanone at the end of the lab procedure. Organic molecules have been labeled A-E so that you can use those abbreviations instead of drawing the structures in the rate laws below. You may also wish to watch the video explaining how to complete the pre-lab assignment, available on Learning Suite What would the rate law be if step 1 were the slowest step and the remaining steps were fast? Show your work. (2 points) 1. 2. What would the rate law be if step 2 were the slowest step, step 1 were in rapid equilibrium, and the remaining steps were fast? Show your work. (3 points) rate What would the rate law be if step 3 were the slowest step, steps 1 and 2 were in rapid equilib- rium, and step 4 were fast? Show your work. (4 points) 3. rate 65

Explanation / Answer

Given the proposed mechanism

1. Rate of reaction from step 1,

rate = k1[Cyclohexanone][H+]

2. when step 2 is slow and step 1 is equilibrium,

rate = (k1/k-1 + k2)[Cyclohexanone][H+]

3. rate from step 3

rate = k3[cyclohexenol][I3-]

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