(a)The magnitude of the force on a charged particle in a magnetic field is given

Question

(a)The magnitude of the force on a charged particle in a magnetic field is given by the equation F = qvB sin().

Select all the correct statements about this from the list below.

1.The force applied by the field is always perpendicular to the velocity.

2.The force applied by the magnetic field is always perpendicular to the field.

3.The velocity and magnetic field are always perpendicular to one another.

4.The force is maximized when the velocity is parallel to the magnetic field.

5.When the velocity and magnetic field are perpendicular to one another, the particle experiences uniform circular motion (assuming no other forces are acting, and the magnetic field is uniform).

6. A magnetic field exerts no force at all on a charged particle if the particle is at rest.

(b) A charged particle moving through a uniform magnetic field will travel at constant speed, and constant kinetic energy. Explain why a magnetic field can only change the direction of the particle's velocity, but it cannot change the magnitude of the velocity.

Explanation / Answer

a) magnetic force, F = q*(v cross B)

so, F is perpendicular to v and B.

1) True

2) True

3) False

4) False

5) True

6) True

b) magnetic force, F = q*(v cross B)

F is always perpendicular to instantaneois velocity.

so, Force can change magnitude of velocity.it can only change direction of the particle.

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