Four identical metal spherees have charges of q_A = -8.0 muC, q_B=-2.0 muC, q_C=

Question

Four identical metal spherees have charges of q_A = -8.0 muC, q_B=-2.0 muC, q_C=+5.0 muC, and q_D= + 12.0 muC. Two of the spherees are brought together so they touch, and then they are separated. Which spherees are they, if the final charge on each one is +5.0 muC? In a similar manner, which three spherees are brought together and then separated, if the final charge on each of the three is +3.0 muC? The final charge on each of the three separated spherees in part (b) is +3.0 muC. How many electrons would have to be added to one of these spherees to make it electrically neutral? The number of significant digits is set to 3; the tolerance is +/-2%

Explanation / Answer

a) qB + qD = (-2.0µC + 12.0µC)/2 = 10 µC)/2 = 5 µC

b) qA + qc + qD = (-8.0µC +5.0µC + 12.0µC)/3 = (9 µC)/3 = 3 µC

c) n= Q/e = (3*10^-6 C)/(1.6*10^-19 C) = 1.875*10^13 electrons

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