1) If you have five capacitors with capacitances 1.3 x 10 -6 F, 1.7 x 10 -6 F, 4
ID: 585377 • Letter: 1
Question
1) If you have five capacitors with capacitances 1.3 x 10-6 F, 1.7 x 10-6 F, 4.2 x 10-6 F, and two 7.9 x 10-6 F in series. What is the equivalent capacitance of all five? C= .5409 x 10-6
2) Initially the capacitors are uncharged. Now a 13 V battery is attached to the system. How much charge is on the positive plate of the 4.2 x 10-6 F capacitor? Q= _____ x 10-6
3)What is the potential difference between the plates of the 4.2 x 10-6 F capacitor? V= ____ V
4) How much energy is stored in the entire capacitor system? PE= _____ x 10-6
5) If you have five capacitors with capacitances 1.3 x 10-6 F, 1.7 x 10-6 F , 4.2 x 10-6 F, and two 7.9 x 10-6 F in parallel. What is the equivalent capacitance of all five? C= _____ x 10-6
6) If one attaches a 13 V battery to the system, how much charge is on the positive plate of the 4.2 x 10-6 F capacitor? Q= ____ x 10-6
7) What is the potential difference between the plates of the 4.0 x 10-6 F capacitor? V= ____ V
8) How much energy is stored in the entire capacitor system? PE= _____ x 10-6 J
Explanation / Answer
In series 1/Ceq = 1/1.3 × 10-6 F + 1/1.7 × 10-6 F + 1/ 4.2 × 10-6 F + 1/7.9 × 10-6 F + 1/7.9 × 10-6 F =1848725.858
1)So 1/Ceq = 1848725...So Ceq = 5.40x10^-7 = 0.540 x10^-6F
2)In series the charge is the same on each capacitor...so using q = Cv
we have q =0.540x10^-6*13 = 7.02x10^-6C
3) v = q/C = 7.02x10^-6/4.2x10^-6 = 1.67V
4) E = 1/2*Ceq*v^2 = 1/2*0.540 x10^-6*13^2 =4.563x10^-5J
5) Now in parallel the Ceq = sum of the capacitor =
1.3 × 10-6 F +1.7 × 10-6 F + 4.2× 10-6 F + 7.9 × 10-6 F +7.9 × 10-6 F = 23x10^-6F
6) Now the voltage is the same over each so q = C*v = 4.2x10^-6*13 = 5.46x10^-5C
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