Three point charges, A = 1.95 meu C, B = 7.15 meu C, and C = -4.55 meu C, are lo

Question

Three point charges, A = 1.95 meu C, B = 7.15 meu C, and C = -4.55 meu C, are located at the corners of an equilateral triangle as in the figure above. Find the magnitude and direction of the electric field at the position of the 1.95 meu C charge. 0.283 magnitude Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. M/C -244.43 direction your response differs from the correct answer by more than 10%. Double check your calculations. "below the phi x-axis How would the electric field at that point be affected if the charge there were doubled? The magnitude of the field would be halved. The field would be unchanged. The magnitude of the field would double. The magnitude of the field would quadrupile. Would the magnitude of the electric force be affected? Yes No

Explanation / Answer

Here ,

a) for the electric field at point A

electric field due to B

EB = k * qB/d^2

EB = 9*10^9 * 7.15 *10^-6/.5^2

EB = 2.57 *10^5 N/C

electric field due to C

EC = k * qC/d^2

EC = 9*10^9* 4.55 *10^-6/0.5^2

EC = 1.64 *10^5 N/C

for the net electric field , theta = 120 degree

Enet = sqrt(2.57^2 + 1.64^2 + 2 * 2.57 * 1.64 * cos(120)) * 10^5

Enet = 2.25 *10^5 N/C

the magnitude oe elecyric field is 2.25 *10^5 N/C

for the direction

direction of electric field = arctan(EB * sin(theta)/(EA + EB * cos(theta)))

direction of electric field = arctan(2.57 * sin(120)/(2.57 * cos(120) + 1.64))

direction of electric field = 80.9 degree

the direction of electric field is 80.9 degree below x axis

c)

the electric field will be same.

d)

the magnitude of electric field will be changed as the charge is changed

Yes

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