The following reaction is a single-step, bimolecular reaction: CH3 Br + NaOH CH3

Question

The following reaction is a single-step, bimolecular reaction: CH3 Br + NaOH CH3OH-NaBr When the concentrations of CH3Br and NaOH are both 0.170 M, the rate of the reaction is 0.0060 M/s. (a) What is the rate of the reaction if the concentration of CH3Br is doubled? Number 0.012 M/S (b) What is the rate of the reaction if the concentration of NaOH is halved? Number 0.003 M s (c) What is the rate of the reaction if the concentrations of CH3Br and NaOH are both increased by a factor of three? Number 0.216 M/s

Explanation / Answer

C)

Answer

0.0540M/s

Explanation

Rate = k [CH3Br][NaOH]

When concentrations of both CH3Br and NaOH increased by three fold

Rate = k 3*[CH3Br]*3*[NaOH]

=9*k[CH3Br][NaOH]

= 9*0.0060M/s

= 0.0540M/s

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