The following reaction is a single-step, bimolecular reaction CH Br NaOH CH, OH+
ID: 940160 • Letter: T
Question
The following reaction is a single-step, bimolecular reaction CH Br NaOH CH, OH+ NaBr When the concentrations of CH3Br and NaoH are both 0.120 M, the rate of the reaction is 0.0020 M/s. (a) What is the rate of the ction if the concentration of CH3Br is doubled? Number 2 x 10 M/ s (b) What is the rate of the reaction if the concentration of NaOH is halved? Number M/ s 5 x 10 (c) What is the rate of the reaction if the concentrations of CH3Br and NaOH are both increased by a factor of four? Number 1.8 x 10 M/ sExplanation / Answer
he has already given it is abimolecular reaction
rate is first order with respect to CH3Br
so if you double theconcentration rate also will be double
= 2x 0.002
= 0.004 or
= 4.0 x 10-3 M/s
similarly if you the caocentration rate also will be half
rate = 0.002 / 2
= 0.001
1.0 x 10-3 M/s
both increased 4 times means rate will be 42 = 16 times will increase
16 x 0.002
= 3.2 x 10-2 M/s
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