7. Potassum chlorate e, KCIO, acts as an oxidizing agent in matches, explosives,

Question

7. Potassum chlorate e, KCIO, acts as an oxidizing agent in matches, explosives, flares, and fi ireworks, In the equation below,it is formed from the element chlorine and potassium hydroxide 3d2 + 6 KOH Kao, + 5 KC1 + 3 H2O rite a conversion factor that could be used to convert between moles of potassium hydroxide and moles of potassium chlorate. a. W How many moles of potassium chlorate form when 5 grams of potassium hydroxide react completely? b. What is the maximum number of moles of KCIOs that could form in the combination of 9.0 moles of Clh with 6.0 moles of KOH? c.

Explanation / Answer

a)As the ratio btween the two is 6:1 to conversion factor is 6.

b) 5 grams KOH = .089(mass 5 gram/molar mass of KOH 56 gram) moles of KOH

For 6 moles of KOH 1 mole of KClO3 id formed so here moles of KClO3 formed will be = (1/6 ) x 0.089=0.0148 moles of KClO3=0.0148 x 74 grams=1.10 grams of KClO3.

c)For the preparation of KClO3 from KOH and Cl2, the balanced equation for same is given below.

3Cl2 + 6KOH=KClO3 + 5 KCl + 3H2O

So for preparation of KClO3 we need half the no. of moles of Cl2 as that of the KOH. So for 6 moles of KOH we need only 3 moles of Cl2 and remaing 6 moles will be unused and from proportion for KOH:Cl2:KClO3=6:3:1, here we will for 6:3 ratio of KOH to Cl2 we will have 1 moles of KCLO3 at max.

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