The pht of a buffer solution that is 0.50 M in Nity and 020 M in NH Cl is 9 65,

Question

The pht of a buffer solution that is 0.50 M in Nity and 020 M in NH Cl is 9 65, N0 0150 mole of solid NaOH is added to 500 0 ml of the buffer then which statemen best explains what happend to the ph of the system? NaOH reacts with 1ts to produce more NH,CI. The ratio of Nty to Nty C in the Henderson-Hasselbaich equation decreases, so the phi decreases slightly NaOH reacts with NH4CI to produce more NiHs, The ratio of NiHs to NH Cl in the The pH of the system increases significantly because strong base is added NaOH reacts with Nis to produce more NH4Cl The ratio of 1Hs to NH4Cl in the Henderson-Hasselbalch equation increases, so the ph increases slighty The ph of the system decreases significantly because strong acid is added endersonHasselbach equation increases, so the pH NaOH reacts with NH4CI to produce more NH3. The ratio of NHs to NH4CI in the H The pH of the system does not change because it is a bufer

Explanation / Answer

NH3 + H2O <--> NH4+ + OH-

When NaOH is added, [NaOH] = 0.015/0.5 M =0.03 M

NH4+ reacts with some OH- ions (not all) released from NaOH to produce NH3­ as given below:

NH4+ + OH- <--> NH3 + H2O

Ratio of NH3/NH4+ will increase in Hendersen- Hesselbalch equation and pH will increase slightly.

Option (F)

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