Question 9 (of 29) Save & Exit Sut Time remaining: 1:41:13 9. Ir 13.9 g of oxyge

Question

Question 9 (of 29) Save & Exit Sut Time remaining: 1:41:13 9. Ir 13.9 g of oxygen react with 33.7 g of calcium to produce calclum oxide, what is the limiting reactant and what mass of calclum oxide is produced? O Calcium is the limiting reactant and 472 g of calcium oxide are produced O Oxygen is the limiting reactant and 24.4 g of calcium oxide are produced O Calcium is the limiting reactant and 472 g of calcium oxide are produced O Oxygen is the limiting reactant and 487g of calcium oxide are produced O Calcium is the limiting reactant and 23.6 g of calcium oxide are produced

Explanation / Answer

mol of O2 = mass/MW = 13.9/32 = 0.43437

mol of Ca = mass/MW = 33.7/40= 0.8425

ratio is:

Ca + 1/2O2 = CaO

then, O2 is in exces

mol of CaO formed = mol of Ca reacted = 0.8425 mol

mass = mol*MW = 0.8425*56.0774 = 47.245 g of CaO

choose:

Calcium as limitin reactant, and produices 47.2 g

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