Name EXPERIMENT 12 MOLECULAR ARCHITECTURE PRE-LABORATORY QUESTIONS llowing prepa
ID: 590575 • Letter: N
Question
Name EXPERIMENT 12 MOLECULAR ARCHITECTURE PRE-LABORATORY QUESTIONS llowing preparatory questions should be answered befors coming to lab. They to introduce you to several ideas that are important to aspects of the experiment. You must turn in your work to your instructor before you will be : The : allowed to begin the experiment. 1. () Give the total number of electrons and write the complete electron configurations for the following elements: a. b. Cu expected: actual: c. Pd (ii) Give the total number of electrons and write the shorthand (beyond the filled noble gas) electron configurations for the following elements: a. Ge b. Pt c. Ho 12-1 HEM1314-YEAR-2017-2018Explanation / Answer
Question-1
a)Total number of electrons or atomic number of fluorine =9
Electronic configuration is 9F = 1s2 2s2 2p5
b) the expected electronic configuration of Cu with 29 electrons: 29Cu= 1s2 2s2 2p6 3s2 3p6 4s2 3d9
but the real electronic configuration is 29Cu= 1s2 2s2 2p6 3s2 3p64s13d10, because the electronic configurations having half filled and fully filled atomic orbitals are more stable.
c)The total number of electrons in palladium =46, or the atomic number is 46.
46Pd =1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10 or 46Pd = [Kr]4d10
Question-2
a) the atomic number of Germanium = 32 or number of electrons =32
Electronic configuration of 32Ge = [Ar]3d10 4s2 4p2 [The atomic number of Ar (noble gas) =18]
b) The total number of electrons in Platinum = 78 or electronic configuration of platinum is
78Pt = [Xe]4f14 5d9 6s1 [The atomic number of Xe (noble gas) =54]
Holmium contain 67 electrons and its electronic configuration is 67Ho =[Xe]4f11 6s2
I hope you got the idea of writing electronic configurations of elements
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.