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previous | 10 of 11I next Correct Using Balanced Equations for Limiting Reactants Elemental S reacts with O2 gas to form SOs gas according to the reaction depicted here. (Figure 1) Limiting reactant Next, consider a situation in which all of the S is consumed before all of the O2 reacts, or one in which you have excess S because all of the O2 has been used up. Part B For each of the given situations, indicate whether S or O2 is the limiting reactan Drag each item to the appropriate bin. Hints Reset Help Figure 1 of1 30 mol sulfur 3.0 mol sulfur 3.0 mol sultfur 0 mol oxygen 4.0 mol oxygen 5.0 mol oxygen Sulfur Limiting reactant is sulfur Limiting reactant is oxygen

Explanation / Answer

B)

the reaction:

S + 3/2O2 = SO3

then...

ratio is 1 : 1.5

a)

limiting is Sulfur --> 3 mol of S and 5 mol of O

b)

limiting is Oxygen --> 3:3 mol ratio, since we need 1.5x more Oxygen than S

limiting is Oxygen --> 3:4 mol ratio, since we need 1.5x more Oxygen than S

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